SOLUTION: three times the age of felicia is four more than the age of isaac. in three years,the sum of their ages will be 30 years.find their present ages.

Algebra ->  Customizable Word Problem Solvers  -> Age -> SOLUTION: three times the age of felicia is four more than the age of isaac. in three years,the sum of their ages will be 30 years.find their present ages.      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1031635: three times the age of felicia is four more than the age of isaac. in three years,the sum of their ages will be 30 years.find their present ages.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
three times the age of felicia is four more than the age of isaac. in three years,the sum of their ages will be 30 years.find their present ages.
---------------------
Equations:
3f = I + 4
f+3 + I+3 = 30
--------------------------
Substitute for "I" and solve for "f"::
f + 3 + 3f-4 + 3 = 30
-----------------------------
4f = 30-2
f = 7 yrs (Felicia's age now)
I = 3f-4 = 17 yrs (Isaac's age now)
-------------
Cheers,
Stan H.
---------------