SOLUTION: A woman bought some large frames for$11 each and some small frames for $7 each at a closeout sale. If she bought 26 frames for $218, find how many of each type she bought.
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Question 1031571: A woman bought some large frames for$11 each and some small frames for $7 each at a closeout sale. If she bought 26 frames for $218, find how many of each type she bought. Answer by Edwin McCravy(20060) (Show Source):
Let the number of large frames be x
Let the number of small frames be y
Cost Cost
Type Number of of
of of EACH ALL
frame frames frame frames
-------------------------------------------
large x $11 $11x
small y $7 $7y
-------------------------------------------
TOTALS 26 ----- $218
The first equation comes from the "number of frames" column.
x + y = 26
The second equation comes from the last column.
11x + 7y = 218
So we have the system of equations:
.
We solve by substitution. Solve the first equation for y:
x + y = 26
y = 26 - x
Substitute (26 - x) for y in 11x + 7y = 218
11x + 7(26 - x) = 218
11x + 182 - 7x = 218
4x + 182 = 218
4x = 36
x = 9 = the number of large frames.
Substitute in y = 26 - x
y = 26 - (9)
y = 17 small frames.
Checking: 9 large frames cost $99 and 17 small frames is $119
That's 26 frames.
And indeed $99 + $119 = $218
Edwin