Question 1031495: Tan(sin^-1 3/5+pi/6)
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Tan(sin^-1 3/5+pi/6)
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= [tan(sin^-1(3/4)) + tan(pi/6)] / [1 - tan(sin^-1(3/4))*tan(pi/6)]
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Note: tan(sin^-1(3/4)) = (3/sqrt(4^2-3^2)) = 3/sqrt(7)
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= [(3/sqrt(7) + (1/sqrt(3))] / [1 - (3/sqrt(7))*(1/sqrt(3)]
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etc.
Cheers,
Stan H.
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