SOLUTION: The length of a rectangular block is three times its width. The surface area is 300cm^2. If the width of the block is xcm, calculate the dimensions of the box and for maximum volum
Algebra ->
Volume
-> SOLUTION: The length of a rectangular block is three times its width. The surface area is 300cm^2. If the width of the block is xcm, calculate the dimensions of the box and for maximum volum
Log On
Question 1031471: The length of a rectangular block is three times its width. The surface area is 300cm^2. If the width of the block is xcm, calculate the dimensions of the box and for maximum volume. Answer by jorel555(1290) (Show Source):
You can put this solution on YOUR website! The area of a rectangle is given by length X width; thus
(3W)(W)=300
3W^2=300
W^2=100
W=sqrt 100, or 10,L=30
Maximum volume is given by a square of area 300cm^2, thus each side is sqrt300cm^2 in size, or approximately 17.32 cms each!!!!!!!
(