Question 1031389: One positive number is 7 more than a second number, and their product is 44.
Answer by bcheng3(1)   (Show Source):
You can put this solution on YOUR website! 1) Define your variables:
x = second positive number
x + 7 = first positive number
2) Write an equation:
x(x + 7) = 44
3) Solve equation:
x^2 + 7x = 44
x^2 + 7x - 44 = 0
(x + 11)(x - 4) = 0
x + 11 = 0 OR x - 4 = 0
x = -11 OR x = 4
However, since -11 isn't positive and the question specifies a positive number and a positive product, we throw away x = -11.
Hence, x = 4, which makes x + 7 = 11, so the two numbers are 4 and 11.
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