SOLUTION: [0,2pi]:2sinx+underroot3=0

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Question 1031322: [0,2pi]:2sinx+underroot3=0
Answer by ikleyn(52879) About Me  (Show Source):
You can put this solution on YOUR website!
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2sin%28x%29+%2B+sqrt%283%29 = 0  --->  sin(x) = -sqrt%283%29%2F2  --->  x = 4pi%2F3  and/or  x = 5pi%2F3.