Question 1031305: An accountant rides a bus part of the way to work every day and walks the rest of the way. The bus averages 38 mph, and the accountant walks at a speed of 5 mph. The distance from home to work is 25 mi, and the total time for the trip is 3 hr. Find how far the accountant walks and how far he rides the bus in miles.
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39620)   (Show Source):
You can put this solution on YOUR website! Basic travel rates rule for R rate, T time, D distance, is RT=D.
You have two ways to assign variables x and y (or whatever two variables you choose).
RATE TIME DISTANCE
RIDE 38 x 38x
WALK 5 y 5y
TOTALS 3 25
OR-------------
RATE TIME DISTANCE
RIDE 38 x/38 x
WALK 5 y/5 y
TOTALS 3 25
Choose the way you want, form the system of equations, and solve.
Answer by MathTherapy(10552)  (Show Source):
You can put this solution on YOUR website!
An accountant rides a bus part of the way to work every day and walks the rest of the way. The bus averages 38 mph, and the accountant walks at a speed of 5 mph. The distance from home to work is 25 mi, and the total time for the trip is 3 hr. Find how far the accountant walks and how far he rides the bus in miles.
Let distance he walks be D
Then distance he rides the bus is: 25 - D
We then get the following TIME equation: 
38D + 5(25 – D) = 3(190) ------- Multiplying by LCD, 190
Solve this equation for D: the distance he walks
Subtract D from 25 to get the distance he rides the bus
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