SOLUTION: Express f(x) = (5-x)(x+1) in standard form.
f(x) =
Find the vertex and axis of symmetry.
vertex (x, y) =
axis of symmetry =
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-> SOLUTION: Express f(x) = (5-x)(x+1) in standard form.
f(x) =
Find the vertex and axis of symmetry.
vertex (x, y) =
axis of symmetry =
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You can put this solution on YOUR website! Express f(x) = (5-x)(x+1) in standard form.
f(x) = -x^2 -x+5x + 5 = -x^2 + 4x + 5
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Find the vertex and axis of symmetry.
Vertex occurs when x = -b/(2a) = -4/(-2) = 2
f(2) = (5-2)(2+1) = 3*3 = 9
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vertex (x, y) = (2,9)
axis of symmetry = x = 2
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Cheers,
Stan H.
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You can put this solution on YOUR website! f(x)=(5-x)(x+1)=5x+5-x^2-x
=-x^2+4x+5. That is standard form. The roots will be (-1,5) to check.
The vertex is at -b/2a=-4/-2=2 for x.
f(2)=-4+8+5=9
(2,9) is the vertex.
axis of symmetry is x=2.