Let the number of nickles be x
Let the number of dimes be y
Value Value
Type Number of of
of of EACH ALL
coin coins coin coins
-------------------------------------------
nickles x $0.05 $0.05x
dimes y $0.10 $0.10y
-------------------------------------------
TOTALS 59 ----- $4.05
The first equation comes from the number of coins column.
x + y = 59
The second equation comes from the last column.
0.05x + 0.10y = 4.05
Get rid of decimals by multiplying every term by 100:
5x + 10y = 405
So we have the system of equations:
.
We solve by substitution. Solve the first equation for y:
x + y = 59
y = 59 - x
Substitute (59 - x) for y in 5x + 10y = 405
5x + 10(59 - x) = 405
5x + 590 - 10x = 405
-5x + 590 = 405
-5x = -185
x = 37 = the number of nickles.
Substitute in y = 59 - x
y = 59 - (37)
y = 22 dimes.
Checking: 37 nickles is $1.85 and 22 dimes is $2.20
That's 59 coins.
And indeed $1.85 + $2.20 = $4.05
Edwin