Question 1031125: Calculate the value of x, if
((Sin^2)x) + 2sinx - 2cosx - (1/2)sin2x = 0
Found 2 solutions by Alan3354, ikleyn:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Calculate the value of x, if
((Sin^2)x) + 2sinx - 2cosx - (1/2)sin2x = 0
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((Sin^2)x) + 2sinx - 2cosx - sinx*cosx = 0
sin*(sin + 2) - cos*(sin + 2) = 0
(sin - cos)*(sin + 2) = 0
x = -2 *** No real solution, ignore.
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sin = cos
x = pi/4, 9pi/4 + 2n*pi, n = any integer
Answer by ikleyn(52915)  (Show Source):
You can put this solution on YOUR website! .
Calculate the value of x, if
((Sin^2)x) + 2sinx - 2cosx - (1/2)sin2x = 0
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
After you get
sin(x) = cos(x),
as the previous tutor got, the continuation is
tan(x) = 1.
Hence, x =  or/and x =  , k = 0, +/-1, +/- 2, . . .
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