SOLUTION: The longest side of an acute isosceles triangle is 8 centimeters. Rounded to the nearest tenth, what is the smallest possible length of one of the two congruent sides?
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Question 1030631: The longest side of an acute isosceles triangle is 8 centimeters. Rounded to the nearest tenth, what is the smallest possible length of one of the two congruent sides? Answer by fractalier(6550) (Show Source):
You can put this solution on YOUR website! Picture an isosceles right triangle for starters...the sides of the triangle are 8/sqrt(2) = 4*sqrt(2). But that is a 90 degree angle...you need a touch less...would make the sides a touch bigger...
so to the nearest tenth, the sides would have to be 5.7 cm each.
