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Question 103062: There are three consecutive odd integers. Three times the largest is seven times the smallest. What are the intergers?
Answer by oberobic(2304)   (Show Source):
You can put this solution on YOUR website! Start with x as the first odd integer. The next odd integer will be x + 2. And the next odd integer after that will be x + 4. (Recall the even integers are between the odd integers.)
We don't know what the numbers for x, x+2, and x+4 are.
But we are told that the 3 times the largest (x+4) = 7 times the smallest (7x)
So, 3(x+4)=7x. Multiplying through to remove the parentheses:
3x+12=7x.
Subtracting 3x from both sides:
12 = 4x
Dividing through by 4:
3 = x.
So the consecutive odd integers are:
x = 3
x+2 = 5
x+4 = 7
ALWAYS check! Does 7x = 3(x+4)?
7x = 7(3) = 21
3(x+4) = 3(7) = 21
Check.
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