Question 1030567: a customer buys five cans of baked beans, four packets of brown sugar and two packets of biscuits from a supermarket. he gives the cashier R150.00 and gets R26.00 in change. a can of baked beans costs half as much as a packet of biscuits whilst a packet of sugar is three rand cheaper than a packet of biscuits.
calculate the cost of a can of baked beans, a packet of sugar and a packet of biscuits?
how much will eight cans of baked beans, one packet of sugar and six packets of biscuits cost?
Answer by Cromlix(4381)   (Show Source):
You can put this solution on YOUR website! Hi there,
Make a packet of biscuits = x
Tin of beans then = x/2
Packet of sugar = x - 3
Change from R150.00 = R26.00
So cost of five cans of baked beans,
four packets of brown sugar
and two packets of biscuits = R124.00
5(x/2) + 4(x - 3) + 2x = R124.00
5x/2 + 4x - 12 + 2x = R124.00
Collect like terms:
5x/2 + 4x + 2x = R124.00 + R12.00
5x/2 + 6x = R136.00
Multiply throughout by 2
5x + 12x = R272.00
17x = R272.00
x = R16.00.
..................
Packet of biscuits = R16.00
Tin of beans = R8.00
Packet of sugar = R13.00
....................
how much will eight cans of baked beans,
one packet of sugar and six packets of biscuits cost?
8(R8.00) + R13.00 + 6(16.00)
= R173.00
Hope this helps :-)
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