SOLUTION: the sum of four consecutive number in an A.P. is 28. the product of the second and third numbers exceeds that of the first and last by 18. find the numbers?
Algebra ->
Customizable Word Problem Solvers
-> Numbers
-> SOLUTION: the sum of four consecutive number in an A.P. is 28. the product of the second and third numbers exceeds that of the first and last by 18. find the numbers?
Log On
Question 1030561: the sum of four consecutive number in an A.P. is 28. the product of the second and third numbers exceeds that of the first and last by 18. find the numbers? Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! let the numbers be a-3d, a-d, a+d, a+3d
sum of them is 28
Add up the terms
4a=28
a=7
(a-d) (a+d) =(a+3d)(a-3d)+18
plug a
(7-d)(7+d)=(7+3d)(7-3d)+18
49-d^2=49-9d^2+18
8d^2=18
d^2=18/8
d^2 =9/4
d= +/- (3/2)
Plug the values of a & d to get the consecutive numbers
