SOLUTION: the area of a square is 81 - 72 x + 16 x^2 if x must be a positive integer, what is the least possible measure for the perimeter of the square

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Question 1030553: the area of a square is 81 - 72 x + 16 x^2 if x must be a positive integer, what is the least possible measure for the perimeter of the square
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
A+=++81+-+72+x+%2B+16+x%5E2+=+%289-4x%29%5E2
==> s+=+sqrt%28%289-4x%29%5E2%29+=+abs%289-4x%29
==> Perimeter is P+=+4abs%289-4x%29
If x = 1, P = 20,
If x = 2, P = 4,
If x = 3, P = 12,
If x = 4, P = 28, etc., ...
Therefore the least possible measure for the perimeter of the square is 4.