SOLUTION: I have to graph y = -x + 3 for slope and y-intercept. I can't seem to find the right way to graph it. Could you help me on this question?

Algebra ->  Graphs -> SOLUTION: I have to graph y = -x + 3 for slope and y-intercept. I can't seem to find the right way to graph it. Could you help me on this question?      Log On


   



Question 1030517: I have to graph y = -x + 3 for slope and y-intercept. I can't seem to find the right way to graph it. Could you help me on this question?
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
To graph using the slope and y-intercept,
you start by plotting the y-intercept point.
Then, using the slope, you find other points.
It works like this:
For y=-x%2B3 ,
the slope is the -1 that is the coefficient of x ,
and the y-intercept, is the 3 that appears as an independent term.
That y-intercept is the y coordinate for the point where the graph crosses the y-axis.
So you mark that point:

From that point you move to the right and left using the slope.
A slope of -1 means that as you move one grid square to the right (as x increases by 1 ),
y increases by -1 (meaning that it decreases by 1 , and you move down one square.
So from point (0,3) you go to (1,2) , and from there to (2,1) , and to (3,0) ,
and to (4,-1), and so on.
Reversing movements you can go one square to the left and one up,\from (0,3) to (-1,4) , and then to (-2,5), and to (-3,6), and so on>
.

Note:
If the slope was 3%2F2 , when going from point to point,
you would move 2 spaces to the right and 3 up,
or reversing, you would move 2 spaces to the left and 3 down.