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Question 1030334: I've been trying to solve and understand these problems for the past 2 hours, and it's killing me. I still don't understand it. Can you please show the work when solving, in hopes that I can see, and understand.
4y^2-16x+8y-12=0
I need to rewrite in standard form, as well as find the vertex,focus, and directrix.
Answer by rothauserc(4718)   (Show Source):
You can put this solution on YOUR website! 4y^2 -16x +8y -12 = 0
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Rewrite grouping like terms
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4y^2 +8y -16x -12 = 0
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Divide both sides of = by 4
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y^2 +2y -4x -3 = 0
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This is a parabola that opens to the right
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y^2 +2y = 4x +3
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Complete the square
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y^2 +2y +1 = 4x +4
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standard form is
(y+1)^2 = 4(x+1)
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Vertex is (-1, -1)
Focus is (0, -1)
Directrix is (x = -2)
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Formulas - parabola opening right
(y-h)^2 = 4p(x-k)
Vertex = (h, k)
Focus = (h+p, k)
Directrix = (x = h - p)
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