Question 1030311: Gustav has 35 dimes and quarters that total $5.00. Solve a system of equations to find out how many dimes and how many quarters he has. Answer by Edwin McCravy(20064) (Show Source):
Let the number of dimes be x
Let the number of quarters be y
Value Value
Type Number of of
of of EACH ALL
coin coins coin coins
-------------------------------------------
dimes x $0.10 $0.10x
quarters y $0.25 $0.25y
-------------------------------------------
TOTALS 35 ----- $5.00
The first equation comes from the "number of coins" column.
x + y = 35
The second equation comes from the last column.
0.10x + 0.25y = 5.00
Get rid of decimals by multiplying every term by 100:
10x + 25y = 500
So we have the system of equations:
.
We solve by substitution. Solve the first equation for y:
x + y = 35
y = 35 - x
Substitute (35 - x) for y in 10x + 25y = 500
10x + 25(35 - x) = 500
10x + 875 - 25x = 500
-15x + 875 = 500
-15x = -375
x = 25 = the number of dimes.
Substitute in y = 35 - x
y = 35 - (25)
y = 10 quarters.
Checking: 25 dimes is $2.50 and 10 quarters is $2.50
That's 35 coins.
And indeed $2.50 + $2.50 = $5.00
Edwin