SOLUTION: n which quadrant on a graph does the center of a circle described by the following equation.
\left(x+7\right)^2+\left(y+4\right)^2=58(x+7)2+(y+4)2=58
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-> SOLUTION: n which quadrant on a graph does the center of a circle described by the following equation.
\left(x+7\right)^2+\left(y+4\right)^2=58(x+7)2+(y+4)2=58
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Question 1030079: n which quadrant on a graph does the center of a circle described by the following equation.
\left(x+7\right)^2+\left(y+4\right)^2=58(x+7)2+(y+4)2=58 Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! (x+7)2+(y+4)2=58
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Center:: (-7,-4)
Ans:: 3rd quadrant
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Cheers,
Stan H.
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