Question 1030076: What is the standard form of the equation of a circle represented by the following equation?
x^2+y^2+4x-2y-11=0 Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! x^2+y^2+4x-2y-11=0
x^2+4x+4+y^2-2y+1=11+4+1=16
(x+2)^2+(y-1)^2=4^2
center at (-2,1) and radius 4.