SOLUTION: What is the shortest distance between the circles defined by x^2-10x +y^2-4y-7=0 and x^2+14x +y^2+6y+49=0?
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Question 1029907
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What is the shortest distance between the circles defined by x^2-10x +y^2-4y-7=0 and x^2+14x +y^2+6y+49=0?
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robertb(5830)
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These two circles intersect at two points that are contained in the line 12x + 5y + 28 = 0 (the radical axis). Therefore the shortest distance between these circles is 0.