SOLUTION: P^4q^-7/(3p)^-2q

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Question 1029888: P^4q^-7/(3p)^-2q
Answer by Boreal(15235) About Me  (Show Source):
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P^4q^-7/(3p)^-2q
The denominator is (1/9)*p^(-2)(q)
The result is 9p^4q^(-7)/p^(-2)*q
9p^6/q^8