SOLUTION: The Lee`s have 3 children. The oldest is twice as old as the youngest. The middle child is 5 years older than the youngest. If the sum of the ages is 57, how old is each child?
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Question 1029881: The Lee`s have 3 children. The oldest is twice as old as the youngest. The middle child is 5 years older than the youngest. If the sum of the ages is 57, how old is each child? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The Lee`s have 3 children. The oldest is twice as old as the youngest. The middle child is 5 years older than the youngest. If the sum of the ages is 57, how old is each child?
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O = 2*Y
M = Y + 5
O + M + Y = 57
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Substitute and solve for "Y"::
2Y + Y+5 + Y = 57
4Y = 52
Y = 13 yrs (youngest)
O = 2Y = 26 yrs
M = Y + 5 = 18 (middle)
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Cheers,
Stan H.
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