SOLUTION: Let x=k be a vertical assymptote of the graph of y=((x^2-2x-15)/(x^3-14x^2+23x+110)). Find the sum of all possible distinct values k. Any help is greatly appreciated!!! Thank

Algebra ->  Trigonometry-basics -> SOLUTION: Let x=k be a vertical assymptote of the graph of y=((x^2-2x-15)/(x^3-14x^2+23x+110)). Find the sum of all possible distinct values k. Any help is greatly appreciated!!! Thank      Log On


   



Question 1029791: Let x=k be a vertical assymptote of the graph of y=((x^2-2x-15)/(x^3-14x^2+23x+110)). Find the sum of all possible distinct values k.
Any help is greatly appreciated!!!
Thank you in advance!
P.S. The answer is 9

Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
Factorize the denominator according to Rational Roots Theorem.
Some of the roots to check for are -1, -2, -4, -5, and 1, 2, 4, 5; and there may be others, according to the theorem, but the smaller sized roots are probably what will be needed.

Going through synthetic division to check for -2 as a root, you will find x%5E2-16x%2B55 with remainder 0. This quadratic factor will have roots according to whatever method you want, of 5 and 11. The denominator of your equation's right hand member is therefore %28x%2B2%29%28x-5%29%28x-11%29.

Now factorize your numerator.
%28x-3%29%28x%2B5%29, your numerator.

Reexpress your equation as highlight%28y=%28%28x-3%29%28x%2B5%29%29%2F%28%28x%2B2%29%28x-5%29%28x-11%29%29%29.

Any factors common to numerator and denominator? No. The factors of the denominator form vertical asymptotes, and there are THREE of them. These three x values for the asymptotes are -2, 5, and 11.

These results do not agree with your reported answer sum of 9.
You can try to rework a solution and MAYBE find any mistake I made.

Answer by ikleyn(52879) About Me  (Show Source):
You can put this solution on YOUR website!
.
Let x=k be a vertical asymptote of the graph of y=((x^2-2x-15)/(x^3-14x^2+23x+110)). Find the sum of all possible distinct values k.
Any help is greatly appreciated!!!
Thank you in advance!
P.S. The answer is 9
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There is much simpler solution.


1. It is easy to guess the roots of the numerator. They are 3 and -5.

2. No one of them is the root of the denominator.
   Hence, the asymptotes x = k are all the roots of the denominator and only they.

3. But the sum of the roots of the denominator is equal to the coefficient at x%5E2 of the denominator, taken with the opposite sign, i.e. 14.

By the way, this solution demonstrates that your answer "9" is wrong.