SOLUTION: Find three consecutive integers
such that twice the first is equal
to 17 more than the largest.
(only an algebraic solution will
be excepted)
How do I solve this?
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-> SOLUTION: Find three consecutive integers
such that twice the first is equal
to 17 more than the largest.
(only an algebraic solution will
be excepted)
How do I solve this?
Ple
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Question 1029682: Find three consecutive integers
such that twice the first is equal
to 17 more than the largest.
(only an algebraic solution will
be excepted)
How do I solve this?
Please help, and thank you!! Answer by fractalier(6550) (Show Source):
You can put this solution on YOUR website! Call the integers, x, x+1, and x+2.
Then we can write
2x = 17 + x+2
2x = x + 19
x = 19
x+1 = 20
x+2 = 21
