Question 1029623:
The diameter of a spherical ball is 18 inches. A circle is painted around the ball so that its center is 3 inches from the center of the sphere.
What is the circumference, to the nearest tenth of an inch, of the painted
circle?
Answer by fractalier(6550)   (Show Source):
You can put this solution on YOUR website! To find the radius, and then the circumference of the drawn circle, picture a triangle with the short leg coming up from the center of the sphere 3 inches. The hypotenuse of the triangle would be the radius of the sphere, 9 inches.
The other leg of the triangle is the radius of the circle in question and can be found using the Pythagorean Theorem...
r^2 = 9^2 - 3^2 = 81 - 9 = 72
so that
r = sqrt(72) = 6*sqrt(2)
C = 2(pi)r = 2(pi)(6*sqrt(2)) = 53.3 inches or so...
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