Question 1029226: If you roll two fair six-sided dice, what is the probability that at least one die shows a 3?
Thanks so much!
Found 2 solutions by Fombitz, Natolino1983: Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website! There are 36 possible outcomes.
1,3
2,3
4,3
5,3
6,3
3,1
3,2
3,3
3,4
3,5
3,6
Eleven of them has at least one three.
Answer by Natolino1983(23) (Show Source):
You can put this solution on YOUR website! First Method:P(at least one 3)= 1-P(none 3)= 1-((5/6)×(5/6)) =1-25/36 =11/36.
Second Method: P(at least a 3) =P(one 3 or two 3) = P(one 3) +P(two 3) = 2x((1/6)×(5/6)) +(1/6)x(1/6) =5/18 + 1/36 = 11/36.
Follow me on Twitter for more @natolino_
|
|
|