SOLUTION: Write the first six terms of the sequence whose nth term is given as; a^n = (-1)n / 2n^2 -3

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Question 1029201: Write the first six terms of the sequence whose nth term is given as;
a^n = (-1)n / 2n^2 -3
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Write the first six terms of the sequence whose nth term is given as;
a(n) = (-1)^n / (2n^2 -3)
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a(1) = -1/(2-3) = -1/-1 = 1
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a(2) = (-1)^2/(2*4-3) = 1/5
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a(3) = (-1)^3/(2(9)-3) = -1/15
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etc.
Cheers,
Stan H.
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