SOLUTION: sqrt( -7 )(sqrt( -4 ) - sqrt( 8 )) and I need to write the result in standard form I'm having trouble simplifying sqrt( -7 ) I got (2i - 2sqrt( 2 )) for (sqrt( -4 ) - sqrt

Algebra ->  Square-cubic-other-roots -> SOLUTION: sqrt( -7 )(sqrt( -4 ) - sqrt( 8 )) and I need to write the result in standard form I'm having trouble simplifying sqrt( -7 ) I got (2i - 2sqrt( 2 )) for (sqrt( -4 ) - sqrt      Log On


   

Question 10292: sqrt( -7 )(sqrt( -4 ) - sqrt( 8 ))
and I need to write the result in standard form
I'm having trouble simplifying sqrt( -7 )
I got (2i - 2sqrt( 2 )) for (sqrt( -4 ) - sqrt( 8 ))
thank you
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt%28+-7+%29%28sqrt%28+-4+%29+-+sqrt%28+8+%29%29

First let's change the square roots of negatives to "i" notation:
i%2Asqrt%287%29+%2A%282%2Ai+-+sqrt%288%29%29
i+%2Asqrt%287%29%2A+2%2Ai+-+i+%2Asqrt%287%29+%2A+sqrt%288%29+
2%2Ai%5E2%2A+sqrt%287%29+-+i%2A+sqrt%287%29+%2Asqrt%284%29+%2Asqrt%282%29+

Remember that i%5E2+=+-1
-2+%2Asqrt%287%29+-+2i%2A+sqrt+%2814%29+

R^2 at SCC