SOLUTION: What are the excluded values? 6/x(x-4) y+5/y^2+3y-18

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Question 1029196: What are the excluded values?
6/x(x-4)
y+5/y^2+3y-18
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
What are the excluded values?
6/x(x-4)
Exclude x = 0 and x = 4
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y+5/y^2+3y-18 = (y+5)/[(y+6)(y-3)]
Exclude x = -6 and x = 3
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Cheers,
Stan H.
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