SOLUTION: The remainder when x^3+3x^2+mx+6 is divided by (x+2) is 14. The value of m is: A. 3 B. 2 C. 1 D.-1 E.-2 How can i tackle this question? working out would be very gratef

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: The remainder when x^3+3x^2+mx+6 is divided by (x+2) is 14. The value of m is: A. 3 B. 2 C. 1 D.-1 E.-2 How can i tackle this question? working out would be very gratef      Log On


   

Question 1029189: The remainder when x^3+3x^2+mx+6 is divided by (x+2) is 14. The value of m is:
A. 3
B. 2
C. 1
D.-1
E.-2
How can i tackle this question? working out would be very grateful!
Answer by Natolino1983(23) About Me  (Show Source):
You can put this solution on YOUR website!
P(x)=x^3+3x^2+mx+6.
P(-2) = -8+12-2m+6 =10-2m =14 then, 2m=-4, m=-2.
Obs:Remainder (P(x)/(x-a)) =P(a).
Answer is m=-2 (E)