Question 1029166: The age of the son and father in the ration of 3:10 .if the father is 56 years older than his son find their ages Answer by Theo(13342) (Show Source):
the age of the son and the father are in the ratio of 3/10.
this means that x/y = 3/10.
the father is 56 years older than the son.
this means that y = x + 56.
in the equation of x/y = 3/10, replace y with x + 56 to get:
x/(x+56) = 3/10.
cross multiply to get 10x = 3*(x+56).
simplify to get 10x = 3x + 168.
subtract 3x from both sides of the equation to get 7x = 168.
divide both sides of the equation by 7 to get x = 24.
the age of the son is 24.
the age of the father is 24 + 56 = 80.
the ratio of the son's age to the father's age is 24/80 = 3/10.
solution looks good.
age of the son is 24.
age of the father is 80.
