SOLUTION: A pole 15 m long rests against a vertical wall at an angle of 60 degree with the ground calculate i) how high up the wall ? ii)How far is the foot of the pole from t

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Question 1029159: A pole 15 m long rests against a vertical wall at an angle of 60 degree with the ground
calculate i) how high up the wall ?
ii)How far is the foot of the pole from the wall?

Answer by Cromlix(4381) About Me  (Show Source):
You can put this solution on YOUR website!
Hi there,
Imagine your problem involves
a right angled triangle.
The pole is the hypotenuse
How high up the wall is the opposite side
How far is the foot of the pole
from the wall is the adjacent side
Using trig ratios:
To find height up wall:
sin = opposite/hypotenuse
sin (60) = opposite/ 15
Opposite = 15 x sin(60)
Opposite = 12.99 m (2 decimal places)
This is how high up the wall the end of the pole is.
cos = adjacent/hypotenuse
cos(60) = adjacent/ 15
Adjacent = 15 x cos(60)
Adjacent = 7.5 m
This is the distance between the foot
of the pole and the wall.
Hope this helps :-)