SOLUTION: What are the excluded values? 6/x(x-4) y+5/y^2 +3y-18

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Question 1029151: What are the excluded values?
6/x(x-4)
y+5/y^2 +3y-18

Answer by Cromlix(4381) About Me  (Show Source):
You can put this solution on YOUR website!
Hi there,
6/x(x - 4) x cannot equal 4 or 0
You cannot have a zero for a denominator.
y + 5/y^2 + 3y - 18
Factorise denominator
y + 5/(y - 3)(y + 6)
y cannot equal 3 or -6
You cannot have a zero for a denominator.
Hope this helps :-)