SOLUTION: Express f(x)=cosx+2sinx as Rcos(x-y) for 0<y<pi/2. Hence find the maximum and minimum points for 0<x<2pi.
I managed to express it as Rcos(x-y) which is sqrt5cos(x-1.11radians).
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Trigonometry-basics
-> SOLUTION: Express f(x)=cosx+2sinx as Rcos(x-y) for 0<y<pi/2. Hence find the maximum and minimum points for 0<x<2pi.
I managed to express it as Rcos(x-y) which is sqrt5cos(x-1.11radians).
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Question 1029015: Express f(x)=cosx+2sinx as Rcos(x-y) for 0
I managed to express it as Rcos(x-y) which is sqrt5cos(x-1.11radians). Answer by Fombitz(32388) (Show Source):