SOLUTION: Express f(x)=cosx+2sinx as Rcos(x-y) for 0<y<pi/2. Hence find the maximum and minimum points for 0<x<2pi. I managed to express it as Rcos(x-y) which is sqrt5cos(x-1.11radians).

Algebra ->  Trigonometry-basics -> SOLUTION: Express f(x)=cosx+2sinx as Rcos(x-y) for 0<y<pi/2. Hence find the maximum and minimum points for 0<x<2pi. I managed to express it as Rcos(x-y) which is sqrt5cos(x-1.11radians).      Log On


   



Question 1029015: Express f(x)=cosx+2sinx as Rcos(x-y) for 0 I managed to express it as Rcos(x-y) which is sqrt5cos(x-1.11radians).
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Looks good to me (the graphs are identical).
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