SOLUTION: sin^-1{{{ sqrt( 3 ) /2 ) }}} cos^-1{{{-sqrt( 3 ) /2) }}} tan^-1(-1) cos^-1{{{cos(4( pi ))/3}}} sin{{{tan^-1(7/24)}}}

Algebra ->  Trigonometry-basics -> SOLUTION: sin^-1{{{ sqrt( 3 ) /2 ) }}} cos^-1{{{-sqrt( 3 ) /2) }}} tan^-1(-1) cos^-1{{{cos(4( pi ))/3}}} sin{{{tan^-1(7/24)}}}      Log On


   

Question 1028759: sin^-1+sqrt%28+3+%29+%2F2+%29+
cos^-1-sqrt%28+3+%29+%2F2%29+
tan^-1(-1)
cos^-1cos%284%28+pi+%29%29%2F3
sintan%5E-1%287%2F24%29
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
sin^-1[sqrt( 3 ) /2 )] = pi/3
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cos^-1[-sqrt( 3 ) /2)] = (5/6)pi
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tan^-1(-1) = (7/4)pi
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cos^-1[cos(4( pi ))/3}] = (4/3)pi
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sin[tan^-1(7/24)]
tan = y/x
y = 7 and x = 24
Then r = sqrt[24^2+7^2] = 25
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Ans:: sin = x/r = 7/25 = 0.28
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Cheers,
Stan H.
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