SOLUTION: I hav used the quadratic formular to find the x-intercepts of y=x^2+2x-5
to be left with x=-1-sqrt(6) and x=-1+sqrt(6)
and now need to find the distance between them which is the
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-> SOLUTION: I hav used the quadratic formular to find the x-intercepts of y=x^2+2x-5
to be left with x=-1-sqrt(6) and x=-1+sqrt(6)
and now need to find the distance between them which is the
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Question 1028747: I hav used the quadratic formular to find the x-intercepts of y=x^2+2x-5
to be left with x=-1-sqrt(6) and x=-1+sqrt(6)
and now need to find the distance between them which is the part I'm stuck on. Found 2 solutions by Alan3354, rothauserc:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! I hav used the quadratic formular to find the x-intercepts of y=x^2+2x-5
to be left with x=-1-sqrt(6) and x=-1+sqrt(6)
and now need to find the distance between them which is the part I'm stuck on.
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Since they're both on the x-axis, it's
-1+sqrt(6) - (-1-sqrt(6))
= 2sqrt(6)
You can put this solution on YOUR website! The x-intercepts are two points on the x-axis
:
(-1-sqrt(6), 0) and (-1+sqrt(6), 0)
:
distance between them = -1+sqrt(6) -(-1-sqrt(6)) =
:
-1+sqrt(6) +1 +sqrt(6) =
:
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2 * sqrt(6)
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