SOLUTION: The second bowl also contained $2.70in pennies and nickels. If there were 54 more pennies than nickels in this bowl, how many were pennies and how many were nickels?

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Question 1028676: The second bowl also contained $2.70in pennies and nickels. If there were 54 more pennies than nickels in this bowl, how many were pennies and how many were nickels?
Answer by Edwin McCravy(20064) About Me  (Show Source):
You can put this solution on YOUR website!
Let the number of nickels be x

there were 54 more pennies than nickels
So then, the number of pennies is x+54

                      Value      Value
Type       Number       of         of
 of          of        EACH       ALL
coin        coins      coin      coins
-------------------------------------------
nickels      x        $0.05       $0.05x
pennies     x+54      $0.01       $0.01(x+54)
-------------------------------------------
                          TOTAL   $2.70


 The equation comes from the last column.
  %28matrix%284%2C1%2CValue%2Cof%2CALL%2Cnickels%29%29%22%22%2B%22%22%28matrix%284%2C1%2CValue%2Cof%2CALL%2Cpennies%29%29%22%22=%22%22%28matrix%285%2C1%2CTotal%2Cvalue%2Cof%2CALL%2Ccoins%29%29

           0.05x + 0.01(x+54) = 2.70

Get rid of decimals by multiplying every term by 100:

                5x + 1(x+54) = 270
                     5x+x+54 = 270
                       6x+54 = 270
                          6x = 216
                           x = 36 nickels 

the number of pennies is x+54,
 
           which equals 36+54 = 90 pennies

Edwin