SOLUTION: Dan competed in a triathlon that covered 46.5 miles. He began by swimming at an average rate of 3mph. Then he biked at an average rate of 20 mph. And finally, he ran at an average
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-> SOLUTION: Dan competed in a triathlon that covered 46.5 miles. He began by swimming at an average rate of 3mph. Then he biked at an average rate of 20 mph. And finally, he ran at an average
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Question 1028663: Dan competed in a triathlon that covered 46.5 miles. He began by swimming at an average rate of 3mph. Then he biked at an average rate of 20 mph. And finally, he ran at an average rate of 6 mph. He spend ½ hour swimming, and the amount of time he spent running was an hour more than the time he spent biking. How long did she spend (a) running and (b) biking? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Dan competed in a triathlon that covered 46.5 miles. He began by swimming at an average rate of 3mph.
Then he biked at an average rate of 20 mph.
And finally, he ran at an average rate of 6 mph.
He spend ½ hour swimming, and the amount of time he spent running was an hour more than the time he spent biking.
How long did HE spend (a) running and (b) biking?
:
let b = the time spent biking
then
(b+1) = the time spent running
:
Write a dist equation; dist = speed * time
swim dist + bike dist + run dist = 46.5 mi
3(.5) + 20b + 6(b+1) = 46.5
1.5 + 20b + 6b + 6 = 46.5
26b + 7.5 = 46.5
26b = 46.5 - 7.5
26b = 39
b = 39/26
b = 1.5 hrs biking
then
1.5 + 1 = 2.5 hrs running
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