SOLUTION: Suppose that the weight of cereal in boxes is labeled to have 20 oz is distributed with mean 20.1 oz and standard deviation .2 oz. Let Y be the weight of the cereal in a random box
Algebra ->
Statistics
-> Describing-distributions-with-numbers
-> SOLUTION: Suppose that the weight of cereal in boxes is labeled to have 20 oz is distributed with mean 20.1 oz and standard deviation .2 oz. Let Y be the weight of the cereal in a random box
Log On
Question 1028660: Suppose that the weight of cereal in boxes is labeled to have 20 oz is distributed with mean 20.1 oz and standard deviation .2 oz. Let Y be the weight of the cereal in a random box. A consumer buys a box of cereal and the weight is 19.7 oz. What is the probability that the weight of cereal is 19.7 oz or less, that is calculate P(Y<19.7)
I am having trouble finding P. Thanks! Answer by rothauserc(4718) (Show Source):
You can put this solution on YOUR website! Use normal distribution
:
Calculate the z-value
:
z-value = (Y - mean) / standard deviation
:
z-value = (19.7 - 20.1) / .2 = -2
:
Consult table of z-values to find probability
:
P ( Y < 19.7 ) = 0.0228
:
