SOLUTION: how would you solve the equation e^4x-1 -3=12?

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Question 1028516: how would you solve the equation e^4x-1 -3=12?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Is this the equation:
+e%5E%28+4x-1%29+-+3+=+12+ ?
If so,.
+e%5E%28+4x-1%29+=+15+
Take the natural log of both sides
+4x+-+1+=+ln%28+15+%29+
+4x+-+1+=+2.708+
+4x+=+3.708+
+x+=+.927+
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check:
+e%5E%28+4x-1%29+-+3+=+12+
+e%5E%28+4%2A.927-1%29+-+3+=+12+
+e%5E%28+3.708+-+1+%29+-+3+=+12+
+e%5E2.708+-+3+=+12+
+14.999+-+3+=+12+
+11.999+=+12+
OK -error due to rounding off