SOLUTION: State the x-coordinate of any holes in the graph of this function: f(x)= (x+3)(6-x) ---------- (x-2)(x+3) A. -3 B. 3 C. 2 D. 0 E. None of the above

Algebra ->  Rational-functions -> SOLUTION: State the x-coordinate of any holes in the graph of this function: f(x)= (x+3)(6-x) ---------- (x-2)(x+3) A. -3 B. 3 C. 2 D. 0 E. None of the above       Log On


   

Question 1028503: State the x-coordinate of any holes in the graph of this function:
f(x)= (x+3)(6-x)
----------
(x-2)(x+3)
A. -3
B. 3
C. 2
D. 0
E. None of the above
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

f%28x%29=+%28%28x%2B3%29%286-x%29%29%2F%28%28x-2%29%28x%2B3%29+%29....simplify
f%28x%29=+%28cross%28%28x%2B3%29%29%286-x%29%29%2F%28%28x-2%29cross%28%28x%2B3%29%29+%29
f%28x%29=+%286-x%29%2F%28x-2+%29
if denominator x-2 is equal to zero, there will be no solution; so, if x=2 there will be hole in the graph of this function
+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+%286-x%29%2F%28x-2+%29%29+
so, answer is: C. 2