SOLUTION: A relief worker needs to divide 2250 bottles of water and 486 cans of food into groups that each contain the same number of items.​ Also, each group must contain the same typ

Algebra ->  Probability-and-statistics -> SOLUTION: A relief worker needs to divide 2250 bottles of water and 486 cans of food into groups that each contain the same number of items.​ Also, each group must contain the same typ      Log On


   



Question 1028465: A relief worker needs to divide 2250 bottles of water and 486 cans of food into groups that each contain the same number of items.​ Also, each group must contain the same type of item​ (bottled water or canned​ food). What is the largest number of relief supplies that can be put in each​ group?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
I need to find the greatest common divisor of
the two numbers
+2250%2F18+=+125+
+486%2F18+=+27+
I think 18 is the GCD, and
18 is the largest number of supplies to be put
into each group
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There are 125 groups that each have 18 bottles of water
There are 27 groups that each have 18 cans of food