SOLUTION: Solve log lower case a (7x+1)=log lower case a (4x+16).

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Question 102837This question is from textbook algebra and trigonometry
: Solve log lower case a (7x+1)=log lower case a (4x+16). This question is from textbook algebra and trigonometry

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Solve log lower case a (7x+1)=log lower case a (4x+16).
Since the logs are equal the anti-logs are equal:
7x+1 = 4x+16
3x = 15
x = 5
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Cheers,
Stan H.