SOLUTION: On opening day chicago cubs star hits a mammoth 465 ft he run. During its flight, the ball traveled at an angle of 26 degrees relative to the field.
How far above the field did
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How far above the field did
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Question 1028346: On opening day chicago cubs star hits a mammoth 465 ft he run. During its flight, the ball traveled at an angle of 26 degrees relative to the field.
How far above the field did the ball land? Answer by addingup(3677) (Show Source):
You can put this solution on YOUR website! 226.78 feet
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Here you have to remember SOHCAHTOA and on this problem we use TOA:
Tangent(26) = Opposite/Adjacent = x/465 (opposite is the rise, the "how far above the field")
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tan(26) = x/465 let's flip it so the unknown is on the left:
x/465 = tan(26) Multiply both sides by 465:
x = tan(26)*465 Use your calculator, calculate tan(26):
x = 0.4877*465 = 226.78
