SOLUTION: find to the nearest degree, all values of x between 0 degrees and 360 degrees that satisfy the equation of 2 sin x + 4 cos 2x =3

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Question 1028339: find to the nearest degree, all values of x between 0 degrees and 360 degrees that satisfy the equation of 2 sin x + 4 cos 2x =3
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
2sinx + 4cos2x = 3 <==> 2sinx+%2B4%281-2sin%5E2%28x%29%29+=+3
<==> 0+=+8sin%5E2%28x%29-2sinx+-+1 <==> 0=%284sinx%2B1%29%282sinx-1%29
==> sinx+=+-1%2F4 or sinx+=+1%2F2
==> x+=+360%5Eo+%2B+sin%5E-1%28-1%2F4%29, or 180%5Eo+-+sin%5E-1%28-1%2F4%29 from the first equation, and
x = 30%5Eo or 150%5Eo from the second equation.
To nearest degree, the answers are 345%5Eo, 194%5Eo, 30%5Eo or 150%5Eo.