SOLUTION: Solve for x Log2(10x)=log2(3x+14) 2log3^x=log3^4 Log5(4x-3)=log5(x+1)

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Solve for x Log2(10x)=log2(3x+14) 2log3^x=log3^4 Log5(4x-3)=log5(x+1)       Log On


   

Question 1028244: Solve for x
Log2(10x)=log2(3x+14)
2log3^x=log3^4
Log5(4x-3)=log5(x+1)
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x
Log2(10x)=log2(3x+14)
If they're base 2:
10x = 3x + 14
7x = 14
x = 2
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2log3^x=log3^4
Not clear.
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Log5(4x-3)=log5(x+1)
Similar to the 1st one.