SOLUTION: {{{ log ((2x+1))=1-log((x-1)) }}}

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Question 1028130: +log+%28%282x%2B1%29%29=1-log%28%28x-1%29%29+
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
log%28%282x%2B1%29%29%2Blog%28%28x-1%29%29=1

log%28%28%282x%2B1%29%28x-1%29%29%29=1

Solution depends on the logarithm base.

b%5E1=%282x%2B1%29%28x-1%29

%282x%2B1%29%28x-1%29=b

2x%5E2-x-1-b=0
You can use general quadratic formula solution to have x in terms of b.