SOLUTION: The length of a rectangle is 2 feet longer than the width. The area of the rectangle is 8 square feet. Draw the graph of the function A(w) that represents this problem. Deter

Algebra ->  Graphs -> SOLUTION: The length of a rectangle is 2 feet longer than the width. The area of the rectangle is 8 square feet. Draw the graph of the function A(w) that represents this problem. Deter      Log On


   

Question 1028034: The length of a rectangle is 2 feet longer than the width. The area of the rectangle is 8 square feet.
Draw the graph of the function A(w) that represents this problem.
Determine the maxima or minima.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
The area is constant and is equal to 8 for all values of w.
Width is also positive.
Neither min nor max, the value is constant.
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