SOLUTION: I'm confused, please help. Solve the system by addition method: Eq 1 states: .18x + .27y = .09 Eq 2 states: .06x - .54y = -.04 Thank you

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: I'm confused, please help. Solve the system by addition method: Eq 1 states: .18x + .27y = .09 Eq 2 states: .06x - .54y = -.04 Thank you      Log On


   



Question 102783This question is from textbook
: I'm confused, please help.
Solve the system by addition method:
Eq 1 states: .18x + .27y = .09
Eq 2 states: .06x - .54y = -.04
Thank you
This question is from textbook

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Let's focus on the first equation: .18x+%2B+.27y+=++.09


100%28.18x+%2B+.27y%29+=++100%28.09%29 Multiply both sides by 100 to move the decimal 2 places to the right. This will make every number a whole number

18x+%2B+27y+=++9 Distribute and multiply

So our first equation is now
Equation 1: 18x+%2B+27y+=++9


Now let's focus on the second equation: .06x+-+.54y+=+-.04


100%28.06x+-+.54y%29+=++100%28-.04%29 Multiply both sides by 100 to move the decimal 2 places to the right. This will make every number a whole number

6x+-+54y+=++-4 Distribute and multiply

So our second equation is now
Equation 2: 6x+-+54y+=++-4


Now let's solve the new system of equations


18x+%2B+27y+=++9
6x+-+54y+=++-4


Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition


Lets start with the given system of linear equations

18%2Ax%2B27%2Ay=9
6%2Ax-54%2Ay=-4

In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).

So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.

So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 18 and 6 to some equal number, we could try to get them to the LCM.

Since the LCM of 18 and 6 is 18, we need to multiply both sides of the top equation by 1 and multiply both sides of the bottom equation by -3 like this:

1%2A%2818%2Ax%2B27%2Ay%29=%289%29%2A1 Multiply the top equation (both sides) by 1
-3%2A%286%2Ax-54%2Ay%29=%28-4%29%2A-3 Multiply the bottom equation (both sides) by -3


So after multiplying we get this:
18%2Ax%2B27%2Ay=9
-18%2Ax%2B162%2Ay=12

Notice how 18 and -18 add to zero (ie 18%2B-18=0)


Now add the equations together. In order to add 2 equations, group like terms and combine them
%2818%2Ax-18%2Ax%29%2B%2827%2Ay%2B162%2Ay%29=9%2B12

%2818-18%29%2Ax%2B%2827%2B162%29y=9%2B12

cross%2818%2B-18%29%2Ax%2B%2827%2B162%29%2Ay=9%2B12 Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.



So after adding and canceling out the x terms we're left with:

189%2Ay=21

y=21%2F189 Divide both sides by 189 to solve for y



y=1%2F9 Reduce


Now plug this answer into the top equation 18%2Ax%2B27%2Ay=9 to solve for x

18%2Ax%2B27%281%2F9%29=9 Plug in y=1%2F9


18%2Ax%2B27%2F9=9 Multiply



18%2Ax%2B3=9 Reduce



18%2Ax=9-3 Subtract 3 from both sides

18%2Ax=6 Combine the terms on the right side

cross%28%281%2F18%29%2818%29%29%2Ax=%286%29%281%2F18%29 Multiply both sides by 1%2F18. This will cancel out 18 on the left side.


x=1%2F3 Multiply the terms on the right side


So our answer is

x=1%2F3, y=1%2F9

which also looks like

(1%2F3, 1%2F9)

Notice if we graph the equations (if you need help with graphing, check out this solver)

18%2Ax%2B27%2Ay=9
6%2Ax-54%2Ay=-4

we get



graph of 18%2Ax%2B27%2Ay=9 (red) 6%2Ax-54%2Ay=-4 (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).


and we can see that the two equations intersect at (1%2F3,1%2F9). This verifies our answer.